9514 1404 393
Answer:
- figure the areas of the rectangle and semicircle
- add them together
Step-by-step explanation:
The area of the rectangle is given by ...
A = LW
A = (20 m)(14 m) = 280 m²
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The area of the semicircle is ...
A = (1/2)πr²
A = (1/2)π(7 m)² = 24.5π m² ≈ 77 m²
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Then the total area is ...
280 m² +77 m² = 357 m²
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The width of the rectangle is the diameter of the circle, which is twice its radius. The area of a semicircle is 1/2 the area of a circle.
The answer is B. you multiply 300 and 15% and it gets you 45 that’d save you money compared to the second incentive
Volume of square pyramid = a²h / 3
Surface area of square pyramid = a² +2a √((a²/4) + h²)
a = base edge
h = height
for the large pyramid;
volume = 648 m³
height = 24 m
Volume = a²h / 3
648 m³ = a² x 24 m / 3
a² = 81 m²
a = 9 m
by applying surface area equation to the large pyramid,
surface area = a² +2a √((a²/4) + h²)
= 9² + 2 x 9 √((9² / 4 ) + 24²
= 520.53 m²
hence surface area of large pyramid = 520.53 m²
Answer:
it's going to be 30 and 18
