How many moles of oxygen are in 6.02 x 10 to the 24th power

a small deviation from the resting membrane potential that occurs because ligand-gated or mechanically-gated channels open or cl

Molodets [167]

Imagine not knowing xhit your literally adc

4 0

2 years ago

If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is

Cloud [144]

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

6 0

2 years ago

Consider the reaction. 2 HBr(g) ¡ H2(g) + Br2(g) a. Express the rate of the reaction in terms of the change in concentration of

Studentka2010 [4]

Answer :

(A) The rate expression will be:

$Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}$

(B) The average rate of the reaction during this time interval is, 0.00176 M/s

(C) The amount of Br₂ (in moles) formed is, 0.0396 mol

Explanation :

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The given rate of reaction is,

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

The expression for rate of reaction :

$\text{Rate of disappearance of }HBr=-\frac{1}{2}\frac{d[HBr]}{dt}$

$\text{Rate of disappearance of }H_2=+\frac{d[H_2]}{dt}$

$\text{Rate of formation of }Br_2=+\frac{d[Br_2]}{dt}$

The rate expression will be:

$Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}$

$\text{Average rate}=-\frac{1}{2}\frac{d[HBr]}{dt}$

$\text{Average rate}=-\frac{1}{2}\frac{(0.512-0.600)M}{(25.0-0.0)s}$

$\text{Average rate}=0.00176M/s$

The average rate of the reaction during this time interval is, 0.00176 M/s

As we are given that the volume of the reaction vessel is 1.50 L.

$\frac{d[Br_2]}{dt}=0.00176M/s$

$\frac{d[Br_2]}{15.0s}=0.00176M/s$

$[Br_2]=0.00176M/s\times 15.0s$

$[Br_2]=0.0264M$

Now we have to determine the amount of Br₂ (in moles).

$\text{Moles of }Br_2=\text{Concentration of }Br_2\times \text{Volume of solution}$

$\text{Moles of }Br_2=0.0264M\times 1.50L$

$\text{Moles of }Br_2=0.0396mol$

The amount of Br₂ (in moles) formed is, 0.0396 mol

8 0

2 years ago

Because single-subject experiments typically involve few participants, there are concerns regarding the __________________ of th

yKpoI14uk [10]

There are questions about the external validity of the results because single-subject experiments frequently only involve a small number of subjects.

<h3>What is experimentation with a single subject?</h3>

A type of quantitative research known as single-subject studies includes closely examining each participant's behavior in a small sample size. It should be noted that the phrase "single-subject" does not necessarily suggest that only one participant is being examined; rather, it usually refers to a group of two to ten.

<h3>What does a single-subject research design aim to achieve?</h3>

Single subject research design is a sort of research methodology that involves monitoring a single phenomena repeatedly over time (often a behavior), and it is typically used to test interventions.

<h3>What features distinguish single-subject studies?</h3>

Changes on the DV can be measured using data gathered before, during, and after the intervention.

learn more about single-subject experiments here

<u>brainly.com/question/13009400</u>

#SPJ4

6 0

1 year ago

Give the characteristic of a second order reaction having only one reactant. Group of answer choices The rate of the reaction is

schepotkina [342]

Answer:

The rate of the reaction is proportional to the square of the concentration of the reactant.

Explanation:

Let us assume a hypothetical reaction in which the rate determining step is the elementary reaction;

2A------> A2

The rate of reaction will be given by:

Rate= k[A]^2

Hence for a second order reaction having only one reactant, the rate of reaction is proportional to the square of the concentration of the reactant. The proportionality constant k, is known as the rate constant of the reaction.

3 0

3 years ago