2 years ago

What is the distance between the points (-4, 2) and (3,-5)?

1 answer:

4 0

Solution:
We are going to find the distance between points A -4; 2, B 3; -5 :
d = √ (xb - xa) 2 + (yb - ya) 2 =

= √ (3 - (-4)) 2 + (-5 - 2) 2 =

= √72 + (-7) 2 = √49 + 49 =
= √98
= 7√2 ≈ 9.899494936611665

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Solve - pv + 40 < 65 for v<br> solve 7w - 3r = 15 for r

Katarina [22]

Answer:

v > -25/p

r = -5 +7/3 w

Step-by-step explanation:

- pv + 40 < 65

Subtract 40 from each side

- pv + 40-40 < 65-40

-pv < 25

Divide each side by -p (remember to flip the inequality since we are dividing by a negative)

-pv/-p > 25/-p

v > -25/p

7w - 3r = 15

Subtract 7w from each side

7w-7w - 3r = 15-7w

-3r = 15-7w

Divide by -3

-3r/-3 = (15-7w)/-3

r = -5 +7/3 w

8 0

2 years ago

It's in the attachment <br> URGENT

maxonik [38]

Step-by-step explanation:

$\frac{2a}{a + b - c} = \frac{2b}{b + c - a} = \frac{2c}{a + c - b} = k \\ \\ by \: theorem \: on \: equal \: ratios \\ \\ \frac{2a + 2b + 2c}{a + b - c + b + c - a + a + c - b} = k \\ \\ \frac{2(a + b + c)}{a + b + c} = k \\ \\ \therefore \: k = 2$