Yep it’s B or 20 outcomes
X+y=8
2x^2-y=-5
elimination method means you link the 2 equations together to make one
these two already have y in the perfect form where you can cancel it out +y and -y so no need to perform any other action to a certain equation.. all you need to do is add them now
2x^2+x=3
Answer:
Approximately 3.5 feet - Option B
Step-by-step explanation:
Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.
( 30 + 2x ) 
( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) ( 20 + 2x )"
600 + 100x + 4
= 1000 - Subtract 1000 on either side, making on side = 0
4 + 100x - 400 = 0 - Take the "quadratic equation formula"
( Quadratic Equation is as follows ) - 
,
,
There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) 
. The approximated value however is 3.5081...or approximately 3.5 feet.
Answer:
Point of the flower garden R ( 11, 44 )
Step-by-step explanation:
Let´s call P ( 3, 14 ) The center of the herb garden, and Q ( 7 , 29 ) the birdbath point
Differences in coordinates of these two points are:
x axis 7 - 3 = 4
y axis 29 - 14 = 15
Then the point Q ( x , y ) will be at: Q ( 11, 44)
x axis x = 11 because 7 + 4 = 11 means that the coordinate 7 is just halfway way between coordinates (x) 3 and 11 ( 4 above 3, and 4 below 11)
Reasoning the same way we conclude y = 44 in this case 29 is just halfway between coordinates (y) 14 and 44 ( 15 above 14 and 15 below 44)
We can probe getting distance d₁ between P and Q and d₂ distance between Q and R as:
d₁ = √ (7-3)² + ( 29-14)²
d₁ = √ 16 + 225
d₂ = √ (11 - 7)² + ( 44 - 29)²
d₂ = √ 16 + 225
