The number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
<h3>How to calculate the permutation</h3>
The formula for permutation is given as;
Permutation =
n = 16
r =4
Permutation =
Permutation =
Permutation = 43, 680 ways
Thus, the number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
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Answer:
B/2
Step-by-step explanation:
Jeez better not get this wrong... anyway, to start off the total is 19 books. Adding 5 then adding 3, She returned 8 books to the 19 she checked out. Uhhhh no clear answer.
NOT the first one cause 8 isn't the total. Don't think it would be the last one cause that's no fun. So it's either the second or the third one. The third one also makes no sense cause it only includes the returns from yesterday. I'm going with the second one
The only option that fits is E, because:
f(10)=4×10+10=50
5(3)-3(-2)
15-(-6)=
15+6=21
a negative plus a negative is a positive so its 21
4(3)-3(-2)
12-(-6)
12+6=18
21+18=39
Basically you multiply the original length by the scale factor. So let's say there's a side length of 10 and the scale factor is .5, then you multiply 10 by .5 and get 5, that's all scale factor is . It can get larger/smaller, just depends on the number.