All possible 3-digit numbers made with only the digits 1 and 2 are written on separate pieces of paper. Without looking, Liam ta
kes one piece. What is the probability that the number on the paper will use just one digit?
1 answer:
To find the probability you need to know the number of desired outcomes (i.e. one digit only used) and the total number of outcomes.
In this case there are 3 desired outcomes - 111, 222, 333.
Since any of the 3 positions in the 3-digit number can be any of 3 numbers, there are 3 x 3 x 3 = 27 total possible outcomes.
The probability of having a desired outcome is 3 / 27 = 1 / 9 = 11.1%
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Step-by-step explanation:
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Answer:
14
Step-by-step explanation:
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28m = 413 - 21
= 392
m = 392/28
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x - y = 16
x^2 + x^2 = 130
----------------
x^2 - y^2 = 256
+(x^2 + y^2 = 130)
2x^2 = 386
x^2 = 193
x = <span>13.892 (3DP)
----
</span>x - y = 16
13.892 - y = 16
-y = 2.108
y = -2.108
The numbers are: 13.892 and -2.108
Answer: 11 u + 14 v
Step-by-step explanation:
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USE CHAIN RULE
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100(t^2+1)^99 * d(t^2+1)
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200t(t^2+1)^99