Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Volumeprism=volumecube times number of cubes
vprism/vcube=number of cubes
vprism=12*5*4.25=255
vcube=side^3=(1/4)^3=1/64
vprism/vcube=255/(1/64)=255*64=16320 cubes
Answer:
128
Step-by-step explanation:
5+2=7
5-2=3
2^5=32
2^2=4
32*4=128
Hope this helps:)
