The answer is 197.
1 and 2 = 3
3+2=5
3+3=6
6x0=0
24x8=192
5+0=5
192+5=197
Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, = a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
yeah probably
Step-by-step explanation:
200 is 80%
200 / 80 = 2.50 (1%)
2.50 * 100 = £250
Hope this helps.