Answer:
Explanation:
This problem relates to interference of light in thin films .
The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index is as follows.
2nt = (2n+1) λ / 2 , n is refractive index of thin layer , t is its thickness , λ is wavelength of light .
2 x 1.5 t = λ / 2 , if n = 0 for minimum thickness.
2 x 1.5 t = 600 / 2 nm
t = 100 nm .
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Answer:
Neither technician
Explanation:
Neither technician is correct.
two bulbs are connected in series one bulb burn out
If one bulb in the series burns out then the circuit will break.
In a series circuit same current passes each resistor.
so, both the technician is incorrect bulb B will not work and current will not increase in the other bulb.
Answer:
False
Explanation:
As we know that, the Balmer series gives the n values as,
.
.
Now the value of wavelength can be calculated as,
.
Here, .
And .
Now,
.
Therefore,
Therefore, the wavelength of Balmer series lies in visible region which is 547 nm.
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