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2 years ago

It is too coldfor liquidwater to existon thesurface.

Physics

1 answer:

emmasim [6.3K]2 years ago

7 0

Mars

Explanation:

Mars is believed to be too cold for liquid water to exist on the surface.

Mars is known as the red planet and the only planet believed to be able support life in it.
It is the last of the inner planets which are made up of rock masses.
The atmosphere of mars is very thin.
Under average conditions, liquid water will immediately freeze on the surface due to its low atmospheric pressure.

Learn more:

Surface ratio of mars and moon brainly.com/question/6443737

#learnwithBrainly

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A person standing a certain distance from an airplane with four equally noisy jet engines is experiencing a sound level of 145 d

Katyanochek1 [597]

Answer:

The sound level is 138.97 dB.

Explanation:

Given that,

Sound level L= 145 dB

We need to calculate the intensity

Using formula of sound intensity

$L=10\log(\dfrac{I}{I_{0}})$

Put the value into the formula

$145=10\log(\dfrac{I}{I_{0}})$

$\log(\dfrac{I}{I_{0}})=\dfrac{145}{10}$

$\log(\dfrac{I}{I_{0}})=14.5$

$\dfrac{I}{I_{0}}=10^{14.5}$

$I=10^{14.5}\times I_{0}$

$I=10^{14.5}\times10^{-12}$

$I=316.2$

We need to calculate the noise of one engine

Using formula of intensity

$I'=\dfrac{I}{4}$

Put the value into the formula

$I'=\dfrac{316.2}{4}$

$I'=79.05$

We need to calculate the intensity level due to one engine

Using formula of sound intensity

$L'=10\log(\dfrac{I'}{I_{0}})$

$L'=10\log(\dfrac{79.05}{10^{-12}})$

$L'=138.97\ dB$

Hence, The sound level is 138.97 dB

5 0

2 years ago

Choose the scientific notation that best represents the standard notation given. 6,840,000,000 m 68.4 x 108 m 6.84 x 108 m 6.84

faust18 [17]

ANSWER

$6.84\times 10^9$

EXPLANATION.

To write in scientific notation means , we write in form,

$k\times 10^n$

Where n is an integer and

$1\le k\:$

The given number is,

$6,840,000,000$

We move the decimal point backward to obtain our k, the n here is 9, because we moved backward 9 times.

This implies that,

$6,840,000,000=6.84\times 10^9$

The correct answer is D

8 0

2 years ago

Read 2 more answers

You attach a 3.10 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched b

dolphi86 [110]

Answer:

0.785 m/s

Explanation:

Hi!

To solve this problem we will use the equation of motion of the harmonic oscillator, i.e.

$x(t) = A cos(\omega t )+B sin(\omega t)$ - (1)

$\frac{dx}{dt}(t) = \omega (B cos(\omega t )- A sin(\omega t)$ - (1)

The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:

$x(0) = 0.100$

$\frac{dx}{dt}(0) = 0$

Since cos(0)=1 and sin(0) = 0:

$x(0)=A$

$\frac{dx}{dt}(0) = -B\omega$

We get

$A =0.100\\B = 0$

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

$x(0.4) = - 0.100$

Since

$x(t) = 0.100 cos(\omega t)\\ -0.100=x(0.4)=0.100cos(\omega 0.4)$

This is the same as:

$-1 = cos(0.4\omega)$

We know that cosine equals to -1 when its argument is equal to:

(2n+1)π

With n an integer

The first time should happen when n=0

Therefore:

π = 0.4ω

ω = π/0.4 -- (2)

Now, the maximum speed will be reached when the potential energy is zero, i.e. when the sping is not stretched, that is when x = 0

With this info we will know at what time it happens:

$0 = x(t) = 0.100cos(\omega t)$

The first time that the cosine is equal to zero is when its argument is equal to π/2

i.e.

$t_{maxV}=\pi /(2\omega)$

And the velocity at that time is:

$\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\omega t_{maxV})\\\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\pi/2)\\$

But sin(π/2) = 1.

Therefore, using eq(2):

$\frac{dx}{dt}(t_{maxV} ) = 0.100*\omega = 0.100\frac{\pi}{0.400} = \pi/4$

And so:

$V_{max} = \pi / 4 =0.785$

6 0

2 years ago

An object has an acceleration of 18.0 m/s/s. If the net force was doubled and the mass were tripled then the new acceleration wo

kenny6666 [7]

Answer:

12.0 m/s²

Explanation:

Newton's second law:

F = ma

Solving for acceleration:

a = F/m

If force is doubled and mass is tripled:

a' = (2F)/(3m)

a' = ⅔ (F/m)

a' = ⅔ (18.0 m/s²)

a' = 12.0 m/s²

4 0

2 years ago

Please help meeeee will mark as brainliest

Katyanochek1 [597]

Answer:

a) pressure means force acted on a body per unit area

6 0

2 years ago

It is too coldfor liquidwater to existon thesurface.​

It is too coldfor liquidwater to existon thesurface.