Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
m<A = 114° , m<Q = 114° , m< D= 66° ,m<U = 66°
x=13
FIRST THREE OPTIONS
A,B,C
Answer:
–2 < x < 3
Step-by-step explanation:
–8 < 2x – 4 < 2
Add 4 to all parts:
–8 + 4 < 2x – 4 + 4 < 2 + 4
Simplify:
–4 < 2x < 6
Divide all parts by 2:
(–4 ÷ 2) < (2x ÷ 2) < (6 ÷ 2)
Simplify:
–2 < x < 3
Answer:
55%
Step-by-step explanation:
Since 44/80 is 0.55*100 is 55%
Hope this helps !
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