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2 years ago

Parallelogram JSTP∼parallelogram BFMY

Mathematics

1 answer:

Serhud [2]2 years ago

8 0

Answer:

$\angle P=\angle Y;$

$\overline {ST}$ and $\overline {FM};$

$\angle T=\angle M;$

$\overline {JP}$ and $\overline {BY}.$

Step-by-step explanation:

Similar figures have proportional corresponding sides and congruent corresponding angles. If parallelogram JSTP is similar to parallelogram BFMY, then

$\angle J=\angle B;$
$\angle S=\angle F;$
$\angle T=\angle M;$
$\angle P=\angle Y;$
$\dfrac{JS}{BF}=\dfrac{ST}{FM}=\dfrac{TP}{MY}=\dfrac{JT}{BM}=\dfrac{JP}{BY}=\dfrac{SP}{FY}.$

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The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.

If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
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