Semester 1:
let the number of students in the art class be 2a, and the number of the students in the gym class be 7a. (check: the ratio is 2a:7a = 2:7)
so the total number of students is 9a.
semester 2:
the 9a students are go to the art class and gym class at a a ratio of 5: 4,
so 5a students go to the art class, and 4a students go to the gym class.
<span>75 students are in art class in second semester means that 5a=75,
so a=75/5=15.
In the 1st semester the number of students was:
art class: 2a=2*15=30
gym class: 7a=7*15=105</span>
Answer and Step-by-step explanation:
Essentially, you are describing the position of point K using the location of the other points on the graph.
<u>Let's start listing some descriptions:</u>
K is:
<em>3 more than H</em>
<em>2 more than J</em>
<em>3 less than L</em>
<em>4 less than M</em>
<em>7 less than N</em>
<em>12 less than P</em>
<em />
<u>Now look at the answer choices and compare it to what we wrote.</u>
We see that the answer choices A, B, and D are incorrect (based on what we wrote), and that answer choice C is correct.
<u>[C. 7 less than N] is the correct answer.</u>
<u></u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
<em><u></u></em>
<em><u>I hope this helps!</u></em>
The answer is the one that has a denominator of X-5 :)
Answer:
✑ Question :
- Is ( 11 , 9 ) , ( 11 , 5 ) , ( 9 , 3 ) a function ?
No , it's not a function.
✎ Reason :
This is not a function because one element 11 of set A is associated to elements 9 and 5 of set B.
♨ Explore about function :
↪ Function is a special type of relation. It is the refinement of relation. In a relation from A to B , every element of set A should have only one ( distinct ) image in B to be a function. In other words , if no two different ordered pairs have the same first component , then it is a function.
Hope I helped!
Have a wonderful day ! ツ
~ ♡
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁