Question

What quadratic equation has roots 7 and -2/3

Answer 1

Answer:

(x-7)(x+2/3)

Step-by-step explanation:

To easily find an equation with said roots, use the intercept form:

y=a(x-p)(x-q), where p and q are your roots.

y=(x-7)(x-(-2/3) = y=(x-7)(x+2/3)