Answer:
A) Sin A + Sin B = 1.2 Sin C
D) Sin C = 2.5 Sin A = 1.25 Sin B
E) Sin A + Sin C = 1.75 B
Step-by-step explanation:
Here, in the given triangle ABC
Base AC = 16 units, AB = 2 units, and BC = 8 units
Now, by Trigonometric Functions:
Comparing first two terms, we get:
........... (1)
Also,
....... (2)
Comparing first and last terms, we get:
.......... (D)
Also, Sin A = 0.5 Sin B
So, the given statement Sin A = 2 Sin B is FALSE
⇒ 2.5 Sin A = 1.25 Sin B .......... (D)
Also, Sin B = 2 Sin A
⇒ Sin A + Sin B = Sin A + 2 Sin A = 3 Sin A
Also, Sin A = 0.4 Sin C
⇒3 Sin A = 3 x (0.4) Sin C = 1.2 Sin C ..
⇒Sin A + Sin B = 1.2 Sin C ........ (A)
B) Sin A - Sin B = 0.4 Sin C - 2 Sin A = 0.4 Sin C - 2 (0.4 Sin C)
= 0.4 Sin C - 0.8 Sin C = -0.4 Sin C
⇒Sin A - Sin B = -0.4 Sin C ........ (B)
So, the given statement is FALSE
E) Sin A + Sin C = 0.5 Sin B + 1.25 B = 1.75 B
⇒ Sin A + Sin C = 1.75 B ....(E)