We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
Answer: h - 5
Step-by-step explanation:
h decreased by 5
h - 5
I'm sorry TnT I don't really know how to explain this but I'm 100% sure my answer is correct. Hope it helped!
Answer:
$14,048.62
Step-by-step explanation:
The interest is 9% per year and compounded 3 times a year, so each compound will be 9%/3 = 3%
The time elapsed will be 15 years and the interest compounded 3 times a year, so the number of compounds happens will be = 15 years* 3 compounds/year= 45x compound.
So basically the money will get 3% interest 45 times. To put into the compounding interest formula, the final account balance will be:
A = P (1 + [ r / n ]) ^ nt
A= amount of the balance after a period of t
P= principal, the initial money deposit( $3,715)
r= rate(9%)
n= number of compound per unit of time(3 times per year)
t= time(15 years)
The calculation will be:
A = P (1 + [ r / n ]) ^ nt
A =
A = $14,048.62
Answer:
-log_4
Step-by-step explanation: