Answer:
There will be 22.5 grams left after 32 hours.
Step-by-step explanation:
A half-life is how long it takes for half of the amount to go away. In this case, we see that we have two half-life periods worth, which you can determine by dividing the total time by the half-life time.
32hrs/8hrs = 4 half lives.
Now we can raise 1/2 to the power of how many half lives we have (2). Then we multiply that by the amount in the sample.
(1/2)^4 * 360
1/16 * 360
22.5 grams
And this is an exponential function.
Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
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Answer:
6, 9, 12, 15, 18
Step-by-step explanation:
Finding multiples is simple, count by 3 for as many times as you can and there are your multiples.
ANSWER
Three (3) cartons of juice
Y=3X+68.25
80=3X+68.25
Subtract 68.25 from both sides
11.75=3X
Divide
11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4
So he can afford 3 juice cartons
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?