F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>
Answer:
88,7 mL of solution
Explanation:
Molarity (Represented as M) is an unit of chemical concentration that is defined as the ratio between moles of solute per liters of solution, that is:
Molarity = moles of solute / Liters of solution
If molarity of KCN solution is 0,0820M and moles of KCN are 7,27x10⁻³ moles:
0,0820M = 7,27x10⁻³ moles / Liters of solution
Liters of solution = 0,0887L = <em>88,7 mL of solution</em>
I hope it helps!
Answer:
chemical
Explanation:
The chemical properties determine the identity of a substance and are not changed when there is no reaction. In the solution, what takes place is a physical change, which is a change of state (for example, going from solid to aqueous form).
Answer:
48.5 mL , just did it on edge
Answer:
<h3>The answer is 8.29 %</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual density = 19.30g/L
error = 20.9 - 19.3 = 1.6
We have
We have the final answer as
<h3>8.29 %</h3>
Hope this helps you
