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2 years ago

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DF bisects EDG. Find FG. the diagram is not scale. PLEASE SHOW ALL STEPS

2 answers:

aleksklad [387]2 years ago

7 0

I hope this helps you

vodomira [7]2 years ago

6 0

<span>In the picture, we have two triangles. Since EDG was bisected, that means angle EDF and angle FDG are equal. We also see that the triangles contain 90 degree angles as well. Since two of three angles are the same, this means the third angle must also be the same. Because the triangles contain the same angle measurements, they are similar. Because they both share the same side, and all three angles, then the two triangles must be congruent. This means that EF = FG or, equivalently n + 9 = 4n - 6 Solve this equation for n, then plug that value into FG</span>

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Dos numeros naturales se diferencian en 7 unidades y la suma de sus cuadrados es 289

NeTakaya

Answer:

15 y 8

Step-by-step explanation:

y = x - 7

x² + y² = 289

sustituir: x² + (x - 7)² = 289

distribuir: x² + x² - 14x + 49 = 289

sustraer + simplificar: 2x² - 14x - 240 = 0

dividir: x² - 7x - 120 = 0

x² - 15x + 8x - 120 = 0

(x - 15)(x + 8) = 0

x = 15, x = -8 --> x ≠ -8 porque -8 no es naturales

sustituir: y = 15 - 7

simplificar: y = 8

6 0

2 years ago

What is the price of a $13 ticket with a 8% sales tax?

HACTEHA [7]

Answer:

$14.04

Step-by-step explanation:

13 + 1.04 = $14.04

5 0

2 years ago

Read 2 more answers

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Ann [662]

Given:

Consider the given function is:

$f(x)=x^2-8x+13$

To find:

The average rate of change of the function over the interval $-1\leq x\leq 6$ .

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

$m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

We have,

$f(x)=x^2-8x+13$

At $x=-1$ ,

$f(-1)=(-1)^2-8(-1)+13$

$f(-1)=1+8+13$

$f(-1)=22$

At $x=6$ ,

$f(6)=(6)^2-8(6)+13$

$f(6)=36-48+13$

$f(6)=1$

Now, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is:

$m=\dfrac{f(6)-f(-1)}{6-(-1)}$

$m=\dfrac{1-22}{7}$

$m=\dfrac{-21}{7}$

$m=-3$

Therefore, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is -3.

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2 years ago

Write the equation for the inverse of y=4arccot(

garri49 [273]

I think you meant "y = 4 arccot (x)."

This is equivalent to:

y
---- = arccot x
4

and so cot (y/4) = x

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2 years ago