How should this relationship be classified?

Mathematics

1 answer:

Vanyuwa [196]2 years ago

8 0

Answer:

Domain = -2, range = -5

Domain =>0, range = 0

domain = 2, range = 5

let y =>f(x)

It can be seen that Function can be linear having common difference 2

F(x) = 2x + 1 for x>0

is satisfied for above values

let's check

F(2) = 2(2)+1 = 4+1 = 5 As given

For x<0 , F(x) = 2x -1

f(-2)= 2(-2) -1= -4-1= -5 As given

For X= 0, F(x)= 2x

So , F(0) = 0 As given

You might be interested in

What is the distance between each pair of points?

saul85 [17]

Answer:

The square root of 145.

Step-by-step explanation:

For this problem, make a right triangle between these two points. To solve for distance, use the Pythagorean formula. We know that one side is 8, and the other side is 9, so square 8 and 9 to get 64 plus 81. When you add these together, you get the square root of 145. You cannot further simplify the square root of 145, so that is the distance between the pair of points.

5 0

2 years ago

Read 2 more answers

Help please, try to explain it in steps for me if u can't that's fine, ty!

Iteru [2.4K]

Answer:

Step-by-step explanation:

We are given that Expression One is:

$2\cdot 10^x$

And Expression Two is:

$4\cdot 10^{x+y}$

We are given that the value of Expression Two is 20,000 times greater than the value of Expression One. And we want to find the value of y. In other words:

$4\cdot 10^{x+y}=20000(2\cdot 10^x)$