Answer:
La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:
(x - a)^2 + (x - b)^2 = R^2
Entonces si miramos a nuestra ecuación:
(x + 2)^2 + (y - 3)^2 = 121
Tendremos el centro en:
(-2, 3)
el radio está dado por:
R^2 = 121
R = √121 = 11
La gráfica de esta circunferencia se puede ver en la imagen de abajo.
Answer:
MQ and QP are equal, MO and OP are equal, x=2
Step-by-step explanation:
QO is a perpendicular bisector of MP meaning that Triangle MQP must be isosceles (if at least two of the following, angle bisector, median, or an altitude, coincide in a triangle, that triangle must be isosceles). In this case an altitude and median coincide in triangle MQP. This means that MQ=QP as the triangle is isosceles. And also MO=OP because QO is a median. Now solving for x, 11=4x+3, 8=4x, x=2. Hope this helps!
11-2m-(n+5+(-m)-3n+8)
11-2m-n-5-m+3n-8
Answer: -2-3m+2n
If you play music then you won't get distracted by the outside world or if you study in a quiet room
Answer:d
Step-by-step explanation:
