From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.
Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10
</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The
least value is 76 and the highest value is 97. The lower and the upper
quartiles are 85 and 94 respectively while the median is 89.
Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9
The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5
Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
Answer:
47.5%
Step-by-step explanation:
You have to first subtract 80 and 42 to find the decrease first. This is 38. Now, you have to divide this by the original number which is 80. So 38 divided by 80 is 0.475.
Now multiply this by 100.
You can easily move the decimal point to the right.
So you would get 47.5%
Hope this helped!
Thus should be fun I know I might do
Well it would be Y= mx+b so in your problem the answer is Y= -2/3x
They would meet 30 times after 10 minutes.
Since Nick and Sally run on the 100m straight track, and Nicks's speed is 3m / s, while Sally's speed is 2m / s, if they both start from two sides of the track, running towards each other continuously, to determine how many times they would meet each other after 10 minutes the following calculation should be performed:
- 30 x 20 + 2 x 20 = 60 + 40 = 100
- 10 minutes = 600 seconds
- 600/20 = X
- 30 = X
Therefore, they would meet 30 times after 10 minutes.
Learn more about maths in brainly.com/question/25849676