Answer:
40
Step-by-step explanation:
- 4(1/2)x - (3/7) = (1/4)
- 4(1/2)x = (1/4) + (3/7)
- (9/2)x = (7+12)/28
-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126
Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have
Therefore, the probability of event A is given by
Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Long division: (x³ + 2) ÷ (x + 1)
<u> </u><u>x² – x + 1 </u>
x³ + 0x² + 0x + 2 | x + 1
<u>– x³ – x²</u> ⋮ ⋮
– x² + 0x ⋮
<u>+ x² + x</u><span> ⋮</span>
+ x + 2
<span> </span> <u>– x – 1</u>
+ 1
Quotient: Q(x) = x² – x – 1;
Remainder: R(x) = + 1.
I hope this helps. =)