Greetings!
"<span>Six times a number increased by 20 is four less than eight times the number. Find the number."...
This would be, as an equation:
</span>
Solve:
Add
4 and
-6x to both sides.
Simplify.
Divide both sides by
2.
Simplify.
<span>
x=12Hope this helps.
-Benjamin
</span>
Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you! mark me as brainliest pls
§ALEX§