The percentage composition of CF4 is %C = 13.64% and %F = 86.36%
The solution are as follows:
Molar mass of CF4 = 88
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>
<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Answer:
a. sulfur difluoride SF₂
b. sulfur hexafluoride SF₆
c. sodium dihydrogen phosphate NaH₂PO₄
d. lithium nitride Li₃N
e. chromium(III) carbonate Cr₂(CO₃)₃
f. tin(II) fluoride SnF₂
g. ammonium acetate NH₄(CH₃COO)
h. ammonium hydrogen sulfate NH₄(HSO₄)
i. cobalt(III) nitrate Co(NO₃)₃
j. mercury(I) chloride Hg₂Cl₂
k. potassium chlorate KClO₃
l. sodium hydride NaH
Explanation:
The names give us information about the composition. First, we mention the cation and then the anion. In the formula, we follow the same order. Each part has a charge but the resulting compound is electrically neutral.
Icy water is just water.
It is a compound.
Answer: 1. Connective Tissue 2.)Epithelial Tissue 3.)Muscle Tissue 4.)Nervous Tissue
Explanation: