If the point U is between points T and V, then the numerical length of TV is 29 units
<h3>How to determine the numerical length of segment TV?</h3>
From the question, we have the following lengths that can be used in our computation:
- Length TU = 18 units
- Length UV = 11 units
The above parameters and representations implies that the point U is between endpoints T and V
This also means that the length TV is longer than the other lengths TU and TV
So, we have the following length equation
TV = TU + UV
Substitute the known values in the above equation
So, we have the following equation
TV = 18 + 11
Evaluate the sum of the like terms in the above equation
So, we have the following equation
TV = 29
Hence, the numerical length of segment TV is 29 units
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<u>Possible question</u>
If tu = 18 and uv = 11 what is tv, if point u is between points t and v
The answer is a since 150/6 is 25
10x10x10x10, you have to multiply 10 by 10 four times, since it's 10 to the power of 4.
First you need to simplify the equation.
y + 3 = 2(x - 1)
y + 3 = 2x - 2
Then you need to put that into slope-intercept form (y = (slope)x + (y intercept))
y + 3 = 2x - 2
-3 -3
y = 2x - 5
The slope is the coefficient of x, so 2 is the slope of the line.