The answer would be in the chart or graph A is 1 B is 2
Answer:
0.333 m/s
Explanation:
avg speed= (total distance)/(total time)
10m/30s
0.333 m/s
Answer:
(A) 10052.2 m/s²
(B) 0.00678 seconds
Explanation:
From the question,
(A) Applying
V² = U²+2as..................... Equation 1
Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.
make a the subject of the equation
a = (V²-U²)/2s........................ Equation 2
Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m
Substitute these values into equation 2
a = (68²-0²)/(2×0.230)
a = 10052.2 m/s²
(B) Using,
a = (V-U)/t......................... Equation 3
Where t= time.
make t the subject of the equation
t = (V-U)/a......................... Equation 4
Given: V = 68 m/s, U = 0 m/s, a = 10052.2
Substitute into equation 4
t = (68-0)/10052.2
t = 0.00678 seconds
A pure substance that cannot be decomposed by ordinary chemical change. . Energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means.
The new weight is 273.8 N
Explanation:
The weight of an object on Earth is given by
where
m is the mass of the object
g is the acceleration of gravity
The acceleration of gravity at the Earth's surface can be rewritten as
where
G is the gravitational constant
M is the Earth's mass
R is the Earth's radius
Substituting into the previous equation,
We said that in normal conditions, the weight of the person is 730 N:
Later, we are said that:
- The mass of the Earth increases by a factor of 6,
- The radius of the Earth increases by a factor of 4,
Substituting into the equation, we find the new weight of the person in these conditions:
So, the new weight is 3/8 of the original weight, therefore:
Learn more about gravity:
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