Answer: ok bet
Step-by-step explanation: theres a picture below and to graph it you simply start with the y coordinate, which is 7. you put 7 on the graph then go down 3 because 3 is negative, then go right one because 1 is postitive. (you get 1 from making the slope into a fraction, -3/1) also remember the formula for this is y=mx+b. its tricky but i hope this helped
The percentage of the revenue is 32% hope this helps!
Answer:
Step-by-step explanation:
Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.
2a + 3b =18
Ricardo can fill up 9 2-card pages, and 6 3-card pages.
a=9, b=0
We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:
a=6, b=2
Add 2 to b once more:
a=3, b=4
One more time:
a=0, b=6:
Thus, Ricardo can display his figures in the following page combinations:
a=9, b=0
a=6, b=2
a=3, b=4
a=0, b=6
Remember that a= number of 2-card pages and b=number of 3-card pages
There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses.
Answer:
e.none of these
Step-by-step explanation:
Computations For CC for Fraction defective
Sample No d p=d/100
1 0 0
2 0 0
3 2 0.02
4 1 0.01
5 0 0
6 1 0.01
7 2 0.02
8 0 0
Total 0.06
3 sigma control limits for p chart are given by:
hence option e is correct
Ooh, fun
what I would do is to make it a piecewise function where the absolute value becomse 0
because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up
so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points
we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5
A.
B.
sepearte the integrals
next one
the last one you can do yourself, it is
the sum is
so the area under the curve is