Answer:
a. adds $10,000 in bank reserves.
Explanation:
Given that
Reserve requirement is 20%
Now if you want to pay back the loan of $10,000 so here the act of paying back the loan is that the amount of loan i.e. $10,00 would get added to the bank reserves
Therefore as per the given situation, the option a is correct
And, the same is to be considered
Thus, all the other options are incorrect
The main difference of the two is the kind of employers who can offer the saving plans. For 403(b) saving plans, this applies to nonprofit companies, schools, government organizations, hospitals and religious groups. They are exempt of some administrative processes making it less costly compared to 401(k) savings plan. 401(k) savings plan is applied on private companies.
Answer:
mediation
Explanation:
The Writers Guild of America and the film studios used a mediator when they started their negotiations. The mediator is an impartial third party that is present during the negotiations and tries to help both parties reach an agreement or settlement. The decisions taken by the mediator are not mutually binding so any party can accept or reject them. A mediator only helps to solve the problem, offers possible solutions, but shouldn't decide anything.
In order for the decisions taken by the third to be binding, the third party must be an arbitrator. In an arbitration process all parties involved must accept the decision of the arbitrator.
Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:
Restrictions:
- High-grade ore:
- Medium-grade ore:
- Low-grade ore:
- No negative hours:
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.