<img src="https://tex.z-dn.net/?f=4%20%5Csqrt%7B40%7D%20%20%2B%207%20%5Csqrt%7B160%7D%20" id="TexFormula1" title="4 \sqrt{40} +

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Nataly [62]

2 years ago

7 \sqrt{160} " alt="4 \sqrt{40} + 7 \sqrt{160} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

dmitriy555 [2]2 years ago

5 0

Answer:

36 $\sqrt{10}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals in the expression

$\sqrt{40}$

= $\sqrt{4(10)}$

= $\sqrt{4}$ × $\sqrt{10}$ = 2 $\sqrt{10}$

$\sqrt{160}$

= $\sqrt{16(10)}$

= $\sqrt{16}$ × $\sqrt{10}$ = 4 $\sqrt{10}$

Thus

4 $\sqrt{40}$ + 7 $\sqrt{160}$

= 4 × 2 $\sqrt{10}$ + 7 × 4 $\sqrt{10}$

= 8 $\sqrt{10}$ + 28 $\sqrt{10}$

= 36 $\sqrt{10}$

irinina [24]2 years ago

3 0

Answer:

Step-by-step explanation:

4 $4\sqrt{40} + 7 \sqrt{160} = 4\sqrt{2*2*2*5} + 7\sqrt{4*4*5*2}\\ = 4*2\sqrt{10} + 7*4\sqrt{10}\\ = 8\sqrt{10} + 28\sqrt{10} \\$

= (8 + 28)√10

= 36√10

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