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2 years ago

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Solve in terms of x and Y

1 answer:

grin007 [14]2 years ago

6 0

To solve<span> for </span>y<span> in </span>terms of x<span>, the </span>y<span> variable must be alone on the left side of the equation. In the sample problem, subtract 8 from each side. The equation then becomes 4y = 1 - 5x.</span>

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How to solve this problem

Marysya12 [62]

0.5(x - 3) + (1.5 - x) = 5x
0.5x - 1.5 + 1.5 - x = 5x
-0.5x = 5x
5x + 0.5x = 0
5.5x = 0
x = 0

5 0

2 years ago

Help ill give brainly

LuckyWell [14K]

Step-by-step explanation:

I would say 5.6 but that's my opinion

8 0

1 year ago

A quality-control inspector examined 100 light bulbs and found 7 defective. At this rate, how many defective bulbs would there

anastassius [24]

Answer: 175 defective bulbs.

Step-by-step explanation:

1. Keeping on mind that the inspector examined 100 light bulbs and found 7 defective, you can calculate the number of defective bulbs that there would be in a lot of 2500 bulbs as following:

- Let's call the number of defective bulbs that there would be in a lot of 2500 bulbs $x$ .

- Then, you have:

$\frac{100}{7}=\frac{2500}{x}$

- Solve for x:

$x=\frac{2500*7}{100}$

$x=175$

2. Then, there would be 175 defective bulbs in a lot of 2500 bulbs.

4 0

2 years ago

The 5th term in a geometric sequence is 40. The 7th term is 10. What is (are) the possible value(s) of the 4th term?

Lena [83]

Answer:

possible values of 4th term is 80 & - 80

Step-by-step explanation:

The general term of a geometric series is given by

$a(n)=ar^{n-1}$

Where a(n) is the nth term, r is the common ratio (a term divided by the term before it) and n is the number of term

Given, 5th term is 40, we can write:

$ar^{5-1}=40\\ar^4=40$

Given, 7th term is 10, we can write:

$ar^{7-1}=10\\ar^6=10$

We can solve for a in the first equation as:

$ar^4=40\\a=\frac{40}{r^4}$

<em>Now we can plug this into a of the 2nd equation:</em>

<em> $ar^6=10\\(\frac{40}{r^4})r^6=10\\40r^2=10\\r^2=\frac{10}{40}\\r^2=\frac{1}{4}\\r=+-\sqrt{\frac{1}{4}} \\r=\frac{1}{2},-\frac{1}{2}$ </em>

<em />

<em>Let's solve for a:</em>

<em> $a=\frac{40}{r^4}\\a=\frac{40}{(\frac{1}{2})^4}\\a=640$ </em>

<em />

Now, using the general formula of a term, we know that 4th term is:

4th term = ar^3

<u>Plugging in a = 640 and r = 1/2 and -1/2 respectively, we get 2 possible values of 4th term as:</u>

$ar^3\\1.(640)(\frac{1}{2})^3=80\\2.(640)(-\frac{1}{2})^3=-80$

possible values of 4th term is 80 & - 80

3 0

3 years ago

A patient receives milligrams (m) of medication per dose. Her doctor orders her medication to be decreased by 25 milligrams. How

kolbaska11 [484]

A (milligrams) - 25 milligrams = C milligrams

3 0

2 years ago