A=pi(radius^2)
630/3.14=200.64
radius=14.16 feet
C=2(pi)(radius)
=3.14(2)(14.16)
=6.28(14.16)
C=88.92
88.92<100
Yes! He has enough fencing to enclose the circular area.
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
Proportional:
82.8 / 92 = 0.9
73.8 / 82 = 0.9
so
FG / 47 = 0.9
FG = 47 * 0.9
FG = 42.3
answer
The distance between 2 campsites is 42.3 m.
Answer:
D. 29% and 22%
Step-by-step explanation:
The known percentages are 34% and 15%. Add these two together to get 49%. All four choices should add up to 100%. So subtract to find what remains:
100% - 49%
= 51%
We don't actually have enough information to determine the percents for summer and winter. BUT the only answer that adds up to 51% is answer D. 29% and 22%.
