The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>
Why?
Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.
We can calculate the vertical force using the following formula:
Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>
Have a nice day!
Airplane with nose up: The plane's speed through the air is the square root of (80 m/s squared) plus (120 m/s squared. The whole picture is a right triangle, and the plane's speed is the hypotenuse. The angle is the angle whose tangent is (80/120). You can get it from a calculator, a book, a slide rule, or online from the site that rhymes with floogle.
The man pulling the load is also a right triangle. The horizontal component is (hypotenuse) times (cosine of the angle). The vertical component is (hypotenuse) times (sine of the same angle). Fill in what you know, look up the sin and cos of 25 degrees and write those in too, and then you can solve for what you have to find.
Answer:
Answere is (D)
Explanation:
Given m1, v and m2
Total circular momentum is conserved: total circular momentum before putty coin collision is equal to total circular momentum after collision.
Let the final circular velocity of the system be V. Initial circular velocity of the putty is zero.
m1v + m2× 0 = (m1 + m2) V
V = m1v/(m1 + m2).
<h2>
Answer:The total momentum before collision is equal to the total momentum after collision.</h2>
Explanation:
Conservation of momentum states that whenever no external force is acting on a system,the total momentum is constant.
When we consider collisions,take the system as the two bodies that are colliding.
There are no external forces acting on the system.The forces that one body exerts on other come under internal forces.
So,momentum can be conserved in this case.
So,the total momentum before collision is equal to the total momentum after collision.
