You’re answer is 21
7(3)= 21 I hope I’m right :))
1/3 of 30 is 10 because you dividing it by 3 and you would get 10.
Now 2/3 of 10 :
10/3=3.3 (2/3 so we have to multiply by 2) 3.3•2=6.6
6.6 has to be estimated because you can't have 6.6 people.
Your answer would be 6. Before I said 7 but you said I was incorrect so the only possibility left is 6.
Hoped I helped!
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>
</span><span>In notation we write respectively
</span>
Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence
Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²
That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers
Answer:
1/3
Step-by-step explanation:
simplify
81^(-1/4)
= 1/81^(1/4)
= 1/[3×3×3×3]^(1/4). (factorize 81)
= 1/[3]^(4/4)
= 1/3