Okay, so total dogs are 49.
So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
Subtracting the 36 from both sides, leaves you with 2x=13.
Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
We can double check it by adding the small and large dogs together, 6.5+42.5, which gives us 49, our total entries.
Answer:
63.
first of all you didn't give me the common number
do i look like a Weezer
I think it’s B
Sorry if I’m wrong
Answer:
No there cannot be.
Step-by-step explanation:
In explaining this question, I would like us to take into account who the barber is,
" the barber is the one who shaves all those, and those only, who do not shave themselves".
This barber cannot be in existence because who would shave him? If he should shave himself then there is a violation of the rule which says he shaves only those who do not shave themselves. If he shaves himself then he ceases to be a barber. And if he does not shave himself then he happens to be under those who must be shaved by the barber, because of what the rule says. But then he is the barber.
This lead us to a contradiction.
Neither is possible so there is no such barber.
Answer:
it might be 3 one according to me