A beam of light (travelling at the speed of light) would take 65 years to go and 65 years to come back from aldebaran, i.e. 130 years. You can send and receive a radio message (travelling at the speed of light, being electromagnetic radiation) taking so 130 years.
Well, let's see. The problem gave you an ordered pair. In other words, you have an 'x' and a 'y' coordinate. All you need to do is put them into the equation.
Step-by-step explanation:
This means that instead of --
-3x - 3y = 125 + 5y = -20
We would have:
-3(-5)-3(-5) = 125(-5) + 5(-5) = -20
From here, you just simplify it into:
30 = -650 = -20
Since the values are not the same, the ANSWER is NO. The ordered pair does not satisfy the following system of equations.
Answer:
1/2.(x+12)=4x-1
x+12=2(4x-1)
x+12=8x-2
Group like terms
12+2=8x-x
14=7x
Divide both sides by 7
x=2
Step-by-step explanation:
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Answer:duuno i wanted to help
Step-by-step explanation:
thnx