<h2>
Answer:</h2>
Option: A is the correct answer.
A) 12y³
<h2>
Step-by-step explanation:</h2>
We are asked to find the monomials which are divisible by 6y².
<em>We know that a monomial is divisible by the other monomial if it contain all the factor of the divisor monomial.</em>
The factors of the divisor monomial are:
6y²=2×3×y×y
A)
12y³
The factor of this dividend monomial is:
12y³=2×2×3×y×y×y
The monomial contains all the factors of the divisior monomial.
Hence, it is divisible by 6y².
B)
24y
The factor of this dividend monomial is:
24y=2×2×2×3×y
The monomial does not contains all the factors of the divisior monomial.
Hence, it is not divisible by 6y².