Answer:
Two shapes are similar when they have the same shape while their sizes may be the same or different
Therefore, two similar shapes are shapes that have a relationship such that the dimensions of one of the shapes can be obtained from the dimensions of the other shape by multiplying by a scale factor
All circles have the same shape and are defined by their center and radius
Given circle with center at 'x' and radius 'r' and circle with center 'y' and radius 's', then there exist a scale factor a = s/r such that we have;
r × a = s
Where a = s/r, we get;
r × s/r = s
We can therefore, obtain a circle with with the same size as the circle with center 'y' and radius 's' by multiplying the radius of the circle with center at 'x' and radius 'r' by a
Therefore the circle with center at 'x' and radius 'r' is similar to the circle with center 'y' and radius 's'
Step-by-step explanation:
I do not know what is your question.
A(0,-1)
B(3√3/3, 2)
Slope of AB = (y₂ - y₁)/(x₂-x₁)
Slope = (2-1)/(√3/3 , -0)
Slope = 1/√3/3 = 1/√3 = √3/3
OR SLOPE = tan(a°) = √3/3 and a° = 30°
Answer:
x=3
Step-by-step explanation:
First, combine like terms on the left side
4x-5x+9=5x-9
-x+9=5x-9
Subtract 9 on both sides
-x=5x-18
Subtract 5x on both sides
-6x= -18
Divide by -6 on both sides
x=3
Hope this helps! :)
Answer:
y = 9.8995
Step-by-step explanation:
This question requires the use of basic trigonometry.
In this problem, we know one of the sides and two of the angles.
Since one of the angles is 45 degrees and the sum of all internal angles of a triangle is 180 degrees, the other angle can only be 45 degrees, making this an isosceles triangle - that is, the length of the other leg, x, is also 7.
You could use the soh cah toa mnemonic to figure it out, but here just using the a^2 + b^2 = c^2 should be sufficient since we know both legs of the triangle.
7^2 + 7^2 = 98, and the square root of 98 gives you about 9.8995, which sounds about right for this situation.
Hope this helped!