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2 years ago

Find all real numbers x such that x^4 ≤ 8x^2 − 16.

Mathematics

1 answer:

Maru [420]2 years ago

4 0

$x^4 \leq 8x^2 -16\\
x^4-8x^2+16\leq0\\
(x^2-4)^2\leq0\\
x^2-4=0\\
x^2=4\\
x=-2 \vee x=2$

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