Answer:
electric potential is 3.31 × V
potential energy is 152 MeV
Explanation:
given data
fragment charge Q = 46 protons = 46 × 1.6 × C
to find out
electric potential and potential energy
solution
we know here distance from fragment d = 2 × m
and constant for electric force k that is 9 × N-m²/C²
so that we can find electric potential = kQ/d
electric potential = 9 × / ( 2 × )
electric potential = 3.31 × V
and
we know relation between electric potential and potential
that is V = U/q
so U will be = qV
now put all value
we get potential energy U
potential energy = 46 × 3.31 ×
potential energy = 1.52 × eV
so potential energy = 152 MeV
Answer:
x ≈ 56 m
Explanation:
vertical initial velocity = = 25 m/s* sin(30°)= 12.5 m/s
height = h
t- time is found solving quadratic equation.
horizontal velocity =
Horizontal velocity is constant, so distance
Given Information:
Frequency of horn = f₀ = 440 Hz
Speed of sound = v = 330 m/s
Speed of bus = v₀ = 20 m/s
Answer:
Case 1. When the bus is crossing the student = 440 Hz
Case 2. When the bus is approaching the student = 414.9 Hz
Case 3. When the bus is moving away from the student = 468.4 Hz
Explanation:
There are 3 cases in this scenario:
Case 1. When the bus is crossing the student
Case 2. When the bus is approaching the student
Case 3. When the bus is moving away from the student
Let us explore each case:
Case 1. When the bus is crossing the student:
Student will hear the same frequency emitted by the horn that is 440 Hz.
f = 440 Hz
Case 2. When the bus is approaching the student
f = f₀ ( v / v+v₀ )
f = 440 ( 330/ 330+20 )
f = 440 ( 330/ 350 )
f = 440 ( 0.943 )
f = 414.9 Hz
Case 3. When the bus is moving away from the student
f = f₀ ( v / v+v₀ )
f = 440 ( 330/ 330-20 )
f = 440 ( 330/ 310 )
f = 440 ( 1.0645 )
f = 468.4 Hz