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2 years ago

HELP ME PLS I NEED THIS NOW

Mathematics

1 answer:

Lyrx [107]2 years ago

4 0

r = radius

Arc length = 2(3.14)r

7.9 cm = r

Plug our values in

Arc length = 2(3.14)(7.9 cm)

Arc length = 49.6 cm

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Tom borrowed $35,000 to remodel his house. At the end of 5-year loan, he had repaid a total of $46,375. At what simple interest

Wewaii [24]

The formula for simple interest is I = prt, where I is the amount of interest, p is the principal borrowed, r is the interest rate written as a decimal number, and t is the amount of time in years. First we find the amount of interest. He borrowed $35000 but paid back $46375. That means he paid 46375-35000 = $11375 in interest. We can now substitute our information into our interest formula:
11375=35000(r)(5)
11375=35000(5)(r) ----- remember that multiplication is commutative
11375=175000r
Divide both sides by 175000 to cancel it:
11375/175000 = 175000r/175000
0.065 = r
To convert this to a percentage, we multiply by 100:
0.065(100) = 6.5%

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2 years ago

Quincy claims that if 80 coats are sold, the outside temperature is likely to be about 42°

nikklg [1K]

No. Quincy should have used the trend line to find the corresponding x value when y=80.

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2 years ago

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Write your question here (Keep it simple and clear to get the best answer) write 6.4 to the nearest whole number

Alina [70]

It would be 6 because it it under .5 so you wouldn't round up

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2 years ago

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Ben and Tom each take a driving test.

GaryK [48]

Answer:

(b)0.56

Step-by-step explanation:

(a)The tree diagram is attached.

P(Ben Fails)=1-0.8=0.2

P(Tom Fails)=1-0.7=0.3

(b)Probability that both will pass their driving test.

P(both will pass)=0.8 X 0.7 =0.56

(c)Probability that only one of them will pass their driving test.

P(Tom Bass, Ben Fails OR Ben Pass, Tom Fails)

=(0.7 X 0.2)+(0.8 X 0.3)

=0.14+0.24

=0.38

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2 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

2 years ago