Answer: The main difference between the three is the mode of transmission. The chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate. Finally, the overhead pass is projected high in the air to avoid defenders.
Explanation:
Answer:
When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and viewer. Unlike other forms of social video, you’ll get more views and engagement if your video
is longer and repeats key points.
Explanation:
When broadcasting live on social media, one should be live for long because in this way one can get more views as audience will increase with time. There should be an interaction with the audience like answering their questions which they write in the comments section. These comments and views will make this video to the top of news feed. Secondly the most important thing is the content of the video. One must focus on the information or knowledge he/she wants to convey and must repeat the key points again and again so that one who has missed the important points will be able catch them later.
Answer:
L/2
Explanation:
Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.
So the distance d between the bar and the pivot should be at least L/2
Explanation:
Given that,
Length of gold wire, l = 4 m
Voltage of battery, V = 1.5 V
Current, I = 4 mA
The resistivity of gold,
Resistance in terms of resistivity is given by :
Also, V = IR
So,
A is area of wire,
, r is radius, r = d/2 (diameter=d)
Out of four option, near option is (C) 17 μm.
The area of the circle with radius r is
A = πr²
The rate of change of area with respect to time is
The rate of change of the radius is given as
Therefore
When r = 10 ft, obtain
Answer: - 40π ft²/s (or - 127.5 ft²/s)