Answer:
You <u>solve</u> the equation.
Step-by-step explanation:
The process of finding variable values that make the equation true is called <em>solving</em> the equation.
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Answer:
Not enough information given. Please type the whole question out.
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
X=20; pqr = 130°
Step-by-step explanation:
They key here is to notice that the instructions say that qs bisects pqr, meaning that it evenly cuts it into 2 pieces. So, to find x, you just solve for x in the equation 3x+5=2x+25. Then, you plug it back into either side of the equation, at which point, you should get 65. Since it is half of pqr, just double it to get your final answer of 130°
