I'm pretty sure the answer is no. A function looks like this: f(x) = mx + c. Let's add another function, f(y) = ny + d. If the x-intercept is the same, we can subtract c and d from their respective equations. f(x) = mx, f(y) = ny. If the domains are the same, then x and y can have the same value, so we divide it out. f(x) = m, f(y) = n. Finally, if the ranges are the same, the value of f(x) = f(y). So by the substitution property, m=n. Since all the variables equal each other, both functions are equal to f(x) = mx+c! Therefore, they can only be the same function.
Answer: No
Well for each pair of x and y value of the table, you can always find the coordinates of that point on the graph.
eg. x=y=-2 you can find the point {-2,-2} on the graph
The answer is 15, hope this helps
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
Obtain the function g(x)
substitute
![g(x)=-\frac{1}{5} [\left|x+3\right|-5]](https://tex.z-dn.net/?f=g%28x%29%3D-%5Cfrac%7B1%7D%7B5%7D%20%5B%5Cleft%7Cx%2B3%5Cright%7C-5%5D)
using a graphing tool
The graph in the attached figure
The vertex is the point (-3,1)
The x-intercepts are the points (-8,0) and (2,0)
The y-intercept is the point (0,0.4)
