Ask question

Ask question

All categories

3 years ago

7

What is the greatest common factor of 54x^3, 18x, 36x^2

1 answer:

Alex73 [517]3 years ago

4 0

It’s 18x because 36 and 54 are both divisible by 18, and 18 can be divisible by 18 (making 1), resulting in 18 being the most common number between the numbers, whereas the ‘x’ is common between all 3 numbers and since the least amount of x is 1, the answer is just x without an exponent

You might be interested in

Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

$\mu$ = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

$F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2$

La aceleración del bloque es $10.9\ \text{m/s}^2$ .

8 0

2 years ago

Find the perimeter of the figure. (Will mark brainliest of correct!)

Lisa [10]

Answer:

24 inches.

Step-by-step explanation:

Add em' all up cuz.

6 0

2 years ago

Read 2 more answers

(6x+9)−(7x+1) find the difference

Bad White [126]

Answer: -x+8
explanation: it’s in its simplest form because it cannot be factored

5 0

1 year ago

Read 2 more answers

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

2 years ago

Quick math help please:)

timofeeve [1]

I think it’s 720 check and see if it’s rightfully

5 0

2 years ago