Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
No, you should have reduced each base to...
3^(3*2x) = 3^(2*(x-3))
and then you can cancel each base
3*2x = 2*(x-3)
6x = 2x-6
4x= -6
x = -3/2
Answer:
$79
Step-by-step explanation:
Answer:
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
Step-by-step explanation:
Given:
log₂(2) = 1
log₂(4) = 2
To evaluate : log₂(3)
Now,
we know that
logₓ(y) = (Here the log has same base in the numerator and the denominator i.e 10)
therefore,
log₂(3) =
also,
log(2) = 0.3010
log(3) = 0.4771
thus,
log₂(3) =
or
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
Answer: 615.4
Step-by-step explanation:
if the radius is 14