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2 years ago

Geometry help needed.. Thank you :)

Mathematics

1 answer:

dedylja [7]2 years ago

5 0

12 - 10i - 14i
= 12 - 24i
------------------

√100 - √-81
= 10 - 9i
------------------

∛8 = 8^1/3
answer is
D. 8^1/3
-----------------

√54x^9y^7 = 3x^4y^3 √6xy
answer
B. 3x^4y^3 √6xy
-----------------

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Vlad1618 [11]

Square root of 27 is the answer

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2 years ago

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Studentka2010 [4]

Answer:

B. √16 × √6

C. √96

Step-by-step explanation:

4√6

4 can be written as a square root.

4 = √16

√16 × √6

The square roots are multiplied, they can be written under one whole square root.

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2 years ago

Please Help! In which of the following intervals does the trigonometric inequality sec(x)

timofeeve [1]

Step-by-step explanation:

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1 year ago

What axis does the independent quantity go on?

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Horizontal
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2 years ago

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a Poisson process at the rate of 5.5 per hour and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$

and we want P(X ≥ 75) = 1-P(X<75). But

$\bf P(X$

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0

2 years ago