Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
For this, just subtract both sides by 12x and <u>your answer will be </u>
N/3>1
n>1*3
n>3 or (3,+∞)
Solution: n>3 or (3, +∞)
Ound your χ2 to three decimal places and round your P-value to four<span> decimal places.) 0. Ask for details; Follow · Report ... </span>Suppose<span> a </span>family stability measure<span> was </span>administered<span> in </span>four public high schools<span> to a </span>sample<span> of </span>24 students<span> who </span>attend<span> the </span>schools<span>. The </span>scores below<span> were obtained. Is there a difference in.</span>
Answer:
answer is B. 3 and 2
Step-by-step explanation:
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