Answer:
Step-by-step explanation:
The fish population after t years can be modeled by the following equation:
In which F(0) is the initial population and r is the constant rate of decay.
Year one the fish population was 18000
This means that 
In year three the fish population was 8000 fish.
Two years later, so 
So
Answer:
y= -x
Step-by-step explanation:
<u>slope- intercept form</u>
y= mx +c, where m is the slope and c is the y-intercept.
Given that the slope is -1, m= -1.
Substitute m= -1 into the equation:
y= -x +c
To find the value of c, substitute a pair of coordinates into the equation.
When x= 2, y= -2,
-2= -2 +c
c= -2 +2
c= 0
Thus, the equation of the line is y= -x.
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
