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2 years ago

50 pts Plz help !!!! What is the physical state of matter of baking soda.

Chemistry

2 answers:

WITCHER [35]2 years ago

8 0

Baking soda is a solid.

Softa [21]2 years ago

8 0

Answer:

Baking soda otherwise known as sodium bicarbonate is a power.

Hope this helps.

- Que

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4 is correct for this one

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2 years ago

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mixas84 [53]

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Cranberry juice is a homogeneous mixture.

Explanation:

Cranberry juice is a clear, red liquid. It is a homogeneous mixture, because you can't see a boundary between the water and the dissolved red substances dissolved in the water.

A is wrong. In oatmeal with raisins, you can tell the raisins from the oatmeal (see below).

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2 years ago

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madreJ [45]

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2 years ago

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.0 gal tank

Usimov [2.4K]

Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.

Since, 1 US gal=3.78 L

Volume of tank in L will be:

$V=13.0 gal(\frac{3.78 L}{1 gal})=49.14 L$

Also, 1 L=1000 mL

Thus,

$V=49.14 L(\frac{1000 mL}{1 L})=49140 mL$

Mass of gasoline can be calculated as follows:

m=d×V

Here, d is density and V is volume thus,

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Therefore, mass of gasoline will be $3.62\times 10^{4}g$ .

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2 years ago

Calcium hydride (cah2) reacts with water to form hydrogen gas: cah2(s) + 2h2o(l) → ca(oh)2(aq) + 2h2(g) how many grams of cah2 a

andreev551 [17]

Using the ideal gas law equation, we can find the number of H₂ moles produced.
PV = nRT
Where P - pressure - 0.811 atm x 101 325 Pa/atm = 82 175 Pa
V - volume - 58.0 x 10⁻³ m³
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation,
82 175 Pa x 58.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 305 K
n = 1.88 mol

The balanced equation for the reaction is as follows;
CaH₂(s) + 2H₂O(l) --> Ca(OH)₂(aq) + 2H₂(g)
stoichiometry of CaH₂ to H₂ is 1:2
When 1.88 mol of H₂ is formed , number of CaH₂ moles reacted = 1.88/2 mol
therefore number of CaH₂ moles reacted = 0.94 mol
Mass of CaH₂ reacted - 0.94 mol x 42 g/mol = 39.48 g of CaH₂ are needed

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2 years ago